2015 Mathematics HSC 3 Unit
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1)
a
A
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2)
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C
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3)
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B
Question ID: 100130030010
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4)
a
C
Question ID: 100130040010
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s
Choose $8$ students from $12$ so $^{12}C_8$
Choose $1$ student from $4$ so $^{4}C_1$
Both events happening so AND event so multiply $^{12}C_8$$\times ^4C_1$
Question ID: 100130040010
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5)
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A
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6)
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D
Question ID: 100130060010
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7)
a
B
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8)
a
B
Question ID: 100130080010
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9)
a
D
Question ID: 100130090010
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10)
a
C
Question ID: 100130100010
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11a)
a
$\frac12x-\frac14\sin2x+c$
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11b)
a
$\theta=\frac{\pi}{4}$ or $\theta=45^\circ$
Question ID: 100130110020
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11c)
a
$-3 < x\le 1$
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11d)
a
$13\left(x+\tan^{-1}\left(\frac{12}{5}\right)\right)$
Question ID: 100130110040
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11e)
a
$\frac14\left(\ln3+\frac23\right)$
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11fi)
a
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11fii)
a
$-1,3,4$
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12ai)
a
$\angle ACB=60^\circ$
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12aii)
a
$\angle ADX=30^\circ$
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12aiii)
a
$\angle CAB=70^\circ$
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12bi)
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12bii)
a
$\left(\frac{-a}{2},\frac{a}{16}\right)$
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12ci)
a
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12cii)
a
$h\approx910$
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12di)
a
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Question ID: 100130120080
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12dii)
a
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Question ID: 100130120090
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12diii)
a
$\approx2.57$
Question ID: 100130120100
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13ai)
a
$x=3,7$
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13aii)
a
$\sqrt{11}$ms$^{-1}$
Question ID: 100130130020
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13aiii)
a
$a=2$, $c=5$, $n=\frac{\sqrt{11}}{2}$
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13bi)
a
$a_2=\left(\begin{array}{cc} 18\\2\end{array}\right)\dfrac{2^{16}}{3^2}$
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13bii)
a
$\left(\begin{array}{cc}18\\9\end{array}\right)\left(\dfrac23\right)^9$
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13c)
a
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13di)
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13dii)
a
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14ai)
a
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Question ID: 100130140010
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14aii)
a
$\frac{\pi}{6}$ below the horizontal
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14aiii)
a
downwards, for explanation see solution
Question ID: 100130140030
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14bi)
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Question ID: 100130140040
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14bii)
a
$x=1-e^{-t}$
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14biii)
a
$\lim_{t\to\infty}x=1$
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$\lim_{t\to\infty}x=1$
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14ci)
a
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14cii)
a
$\left(\begin{array}{cc}4\\4\end{array}\right)\left(\dfrac12\right)^5+\left(\begin{array}{cc}5\\4\end{array}\right)\left(\dfrac12\right)^6+\left(\begin{array}{cc}6\\4\end{array}\right)\left(\dfrac12\right)^7$
Question ID: 100130140080
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$\left(\begin{array}{cc}4\\4\end{array}\right)\left(\dfrac12\right)^5+\left(\begin{array}{cc}5\\4\end{array}\right)\left(\dfrac12\right)^6+\left(\begin{array}{cc}6\\4\end{array}\right)\left(\dfrac12\right)^7$
Question ID: 100130140080
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14ciii)
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Question ID: 100130140090
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Answers
1) A
2) C
3) B
4) C
5) A
6) D
7) B
8) B
9) D
10) C
11a) $\frac12x-\frac14\sin2x+c$
11b) $\theta=\frac{\pi}{4}$ or $\theta=45^\circ$
11c) $-3 < x\le 1$
11d) $13\left(x+\tan^{-1}\left(\frac{12}{5}\right)\right)$
11e) $\frac14\left(\ln3+\frac23\right)$
11fi) show that question
look at solution
11fii) $-1,3,4$
12ai) $\angle ACB=60^\circ$
12aii) $\angle ADX=30^\circ$
12aiii) $\angle CAB=70^\circ$
12bi) show that question
look at solution
12bii) $\left(\frac{-a}{2},\frac{a}{16}\right)$
12ci) show that question
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12cii) $h\approx910$
12di) show that question
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12dii) show that question
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12diii) $\approx2.57$
13ai) $x=3,7$
13aii) $\sqrt{11}$ms$^{-1}$
13aiii) $a=2$, $c=5$, $n=\frac{\sqrt{11}}{2}$
13bi) $a_2=\left(\begin{array}{cc} 18\\2\end{array}\right)\dfrac{2^{16}}{3^2}$
13bii) $\left(\begin{array}{cc}18\\9\end{array}\right)\left(\dfrac23\right)^9$
13c) proof question
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13di) proof question
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13dii) show that question
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14ai) show that question
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14aii) $\frac{\pi}{6}$ below the horizontal
14aiii) downwards, for explanation see solution
14bi) show that question
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14bii) $x=1-e^{-t}$
14biii) $\lim_{t\to\infty}x=1$
14ci) explain question
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14cii) $\left(\begin{array}{cc}4\\4\end{array}\right)\left(\dfrac12\right)^5+\left(\begin{array}{cc}5\\4\end{array}\right)\left(\dfrac12\right)^6+\left(\begin{array}{cc}6\\4\end{array}\right)\left(\dfrac12\right)^7$
14ciii) proof question
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Solutions
1)
2)
3)
4) Choose $8$ students from $12$ so $^{12}C_8$
Choose $1$ student from $4$ so $^{4}C_1$
Both events happening so AND event so multiply $^{12}C_8$$\times ^4C_1$
5)
6)
7)
8)
9)
10)
11a)
11b)
11c)
11d)
11e)
11fi)
11fii)
12ai)
12aii)
12aiii)
12bi)
12bii)
12ci)
12cii)
12di)
12dii)
12diii)
13ai)
13aii)
13aiii)
13bi)
13bii)
13c)
13di)
13dii)
14ai)
14aii)
14aiii)
14bi)
14bii)
14biii) $\lim_{t\to\infty}x=1$
14ci)
14cii) $\left(\begin{array}{cc}4\\4\end{array}\right)\left(\dfrac12\right)^5+\left(\begin{array}{cc}5\\4\end{array}\right)\left(\dfrac12\right)^6+\left(\begin{array}{cc}6\\4\end{array}\right)\left(\dfrac12\right)^7$
14ciii)